image


1T6-520 Dumps

1T6-520 Braindumps 1T6-520 Real Questions 1T6-520 Practice Test

1T6-520 Actual Questions


Network-General


1T6-520


Application Performance Analysis and Troubleshooting


https://killexams.com/pass4sure/exam-detail/1T6-520


A large Window size used by a client could cause .


  1. The server to consume more resources

  2. Increased number of ACKs to be sent

  3. Increased delay when frames are lost

  4. None of the above


Answer: D


QUESTION: 114

The slowest component on a server will be .


  1. Random Access Memory (RAM)

  2. Disk I/O

  3. Central Processing Unit (CPU)

  4. The constraint (bottleneck)


Answer: D


QUESTION: 115

Round-trip distance latency between San Diego and Salt Lake City (1,850 miles or 2,960

km) is .


  1. About 17 microseconds

  2. About 33 milliseconds

  3. 0.016.818 seconds

  4. Can not be calculated with the information provided


Answer: B


QUESTION: 116

A well documented application profile may be used to .


  1. Identify constraints in the design of the network

  2. Document how an application will perform on the network

  3. Identify the constraints (bottlenecks) that will affect application performance

  4. All of the above


Bandwidth latency can be calculated for a complete user task.


  1. TRUE

  2. FALSE


Answer: A


QUESTION: 118

When applying the predictive analysis model to an application we need to include

in our analysis.


  1. Statistics from the Sniffer Expert Connection layer

  2. Speed of the slowest link between client and server

  3. TCP window size

  4. All of the above


Answer: D


QUESTION: 119

The number of application turns involved in a conversation where the window size is 8760 and the data transmitted is 642,400 would be .


A.

36

B.

42

C.

73

D.

87


Answer: C


QUESTION: 120

A bandwidth consumption graph can help us determine without constraint.


  1. The total amount of data sent by the client

  2. The total amount of data sent by the server

  3. The maximum amount of data sent on a bits per second basis

  4. The maximum amount of data needed by the client


Answer: C


image

6$03/( 48(67,216


7KHVH TXHVWLRQV DUH IRU GHPR SXUSRVH RQO\ )XOO YHUVLRQ LV XS WR GDWH DQG FRQWDLQV DFWXDO TXHVWLRQV DQG DQVZHUV


.LOOH[DPV FRP LV DQ RQOLQH SODWIRUP WKDW RIIHUV D ZLGH UDQJH RI VHUYLFHV UHODWHG WR FHUWLILFDWLRQ H[DP SUHSDUDWLRQ 7KH SODWIRUP SURYLGHV DFWXDO TXHVWLRQV H[DP GXPSV DQG SUDFWLFH WHVWV WR KHOS LQGLYLGXDOV SUHSDUH IRU YDULRXV FHUWLILFDWLRQ H[DPV ZLWK FRQILGHQFH +HUH DUH VRPH NH\ IHDWXUHV DQG VHUYLFHV RIIHUHG E\ .LOOH[DPV FRP


$FWXDO ([DP 4XHVWLRQV .LOOH[DPV FRP SURYLGHV DFWXDO H[DP TXHVWLRQV WKDW DUH H[SHULHQFHG LQ WHVW FHQWHUV 7KHVH TXHVWLRQV DUH XSGDWHG UHJXODUO\ WR HQVXUH WKH\ DUH XS WR GDWH DQG UHOHYDQW WR WKH ODWHVW H[DP V\OODEXV %\ VWXG\LQJ WKHVH DFWXDO TXHVWLRQV FDQGLGDWHV FDQ IDPLOLDUL]H WKHPVHOYHV ZLWK WKH FRQWHQW DQG IRUPDW RI WKH UHDO H[DP


([DP 'XPSV .LOOH[DPV FRP RIIHUV H[DP GXPSV LQ 3') IRUPDW 7KHVH GXPSV FRQWDLQ D FRPSUHKHQVLYH FROOHFWLRQ RI TXHVWLRQV DQG DQVZHUV WKDW FRYHU WKH H[DP WRSLFV %\ XVLQJ WKHVH GXPSV FDQGLGDWHV FDQ HQKDQFH WKHLU NQRZOHGJH DQG LPSURYH WKHLU FKDQFHV RI VXFFHVV LQ WKH FHUWLILFDWLRQ H[DP


3UDFWLFH 7HVWV .LOOH[DPV FRP SURYLGHV SUDFWLFH WHVWV WKURXJK WKHLU GHVNWRS 9&( H[DP VLPXODWRU DQG RQOLQH WHVW HQJLQH 7KHVH SUDFWLFH WHVWV VLPXODWH WKH UHDO H[DP HQYLURQPHQW DQG KHOS FDQGLGDWHV DVVHVV WKHLU UHDGLQHVV IRU WKH DFWXDO H[DP 7KH SUDFWLFH WHVWV FRYHU D ZLGH UDQJH RI TXHVWLRQV DQG HQDEOH FDQGLGDWHV WR LGHQWLI\ WKHLU VWUHQJWKV DQG ZHDNQHVVHV


*XDUDQWHHG 6XFFHVV .LOOH[DPV FRP RIIHUV D VXFFHVV JXDUDQWHH ZLWK WKHLU H[DP GXPSV 7KH\ FODLP WKDW E\ XVLQJ WKHLU PDWHULDOV FDQGLGDWHV ZLOO SDVV WKHLU H[DPV RQ WKH ILUVW DWWHPSW RU WKH\ ZLOO UHIXQG WKH SXUFKDVH SULFH 7KLV JXDUDQWHH SURYLGHV DVVXUDQFH DQG FRQILGHQFH WR LQGLYLGXDOV SUHSDULQJ IRU FHUWLILFDWLRQ H[DPV


8SGDWHG &RQWHQW .LOOH[DPV FRP UHJXODUO\ XSGDWHV LWV TXHVWLRQ EDQN DQG H[DP GXPSV WR HQVXUH WKDW WKH\ DUH FXUUHQW DQG UHIOHFW WKH ODWHVW FKDQJHV LQ WKH H[DP V\OODEXV 7KLV KHOSV FDQGLGDWHV VWD\ XS WR GDWH ZLWK WKH H[DP FRQWHQW DQG LQFUHDVHV WKHLU FKDQFHV RI VXFFHVV


7HFKQLFDO 6XSSRUW .LOOH[DPV FRP SURYLGHV IUHH [ WHFKQLFDO VXSSRUW WR DVVLVW FDQGLGDWHV ZLWK DQ\ TXHULHV RU LVVXHV WKH\ PD\ HQFRXQWHU ZKLOH XVLQJ WKHLU VHUYLFHV 7KHLU FHUWLILHG H[SHUWV DUH DYDLODEOH WR SURYLGH JXLGDQFH DQG KHOS FDQGLGDWHV WKURXJKRXW WKHLU H[DP SUHSDUDWLRQ MRXUQH\


'PS .PSF FYBNT WJTJU IUUQT LJMMFYBNT DPN WFOEPST FYBN MJTU

.LOO \RXU H[DP DW )LUVW $WWHPSW *XDUDQWHHG