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            Python



            PCEP-30-02







            PCEP - Certified Entry-Level Python Programmer










            https://killexams.com/pass4sure/exam-detail/PCEP-30-02


































    Question: 33


    Consider the following code snippet:

    w = bool(23)


    x = bool('')

    y = bool(' ')

    z = bool([False])


    Which of the variables will contain False?

    A. z
    B. x
    C. y
    D. w

    Answer: B


    Explanation:

    Topic: type casting with bool()


    Try it yourself:

    print(bool(23)) # True

    print(bool('')) # False

    print(bool(' ')) # True

    print(bool([False])) # True


    The list with the value False is not empty and therefore it becomes True

    The string with the space also contain one character

    and therefore it also becomes True


    The values that become False in Python are the following:

    print(bool('')) # False

    print(bool(0)) # False

    print(bool(0.0)) # False

    print(bool(0j)) # False

    print(bool(None)) # False


    print(bool([])) # False

    print(bool(())) # False

    print(bool({})) # False

    print(bool(set())) # False

    print(bool(range(0))) # False





    Question: 34


    What is the expected output of the following code?

    def func(num):


    res = '*'

    for _ in range(num):

    res += res


    return res

    for x in func(2):

    print(x, end='')


    A. **
    B. The code is erroneous.
    C. *
    D. ****

    Answer: D


    Explanation:

    Topics: def return for

    Try it yourself:


    def func(num):

    res = '*'

    for _ in range(num):

    res += res

    return res

    for x in func(2):


    print(x, end='') # ****

    # print(x, end='-') # *-*-*-*-

    print()

    print(func(2)) # ****

    The for loop inside of the function will iterate twice.


    Before the loop res has one star.

    In the first iteration a second star is added.

    res then has two stars.

    In the second iteration two more stars are added to those two star and res will end up with four stars.

    The for loop outside of the function will just iterate through the string and print every single star.


    You could get that easier by just printing the whole return value.




    Question: 35


    What is the expected output of the following code?

    num = 1


    def func():

    num = num + 3

    print(num)


    func()


    print(num)

    A. 4 1
    B. 4 4
    C. The code is erroneous.
    D. 1 4
    E. 1 1

    Answer: C


    Explanation:

    Topics: def shadowing


    Try it yourself:

    num = 1

    def func():

    # num = num + 3 # UnboundLocalError: ...

    print(num)

    func()


    print(num)

    print('----------')

    num2 = 1

    def func2():

    x = num2 + 3


    print(x) # 4

    func2()

    print('----------')

    num3 = 1

    def func3():


    num3 = 3 # Shadows num3 from outer scope

    print(num3) # 3

    func3()

    A variable name shadows into a function.

    You can use it in an expression like in func2()


    or you can assign a new value to it like in func3()

    BUT you can not do both at the same time like in func()

    There is going to be the new variable num


    and you can not use it in an expression before its first assignment.




    Question: 36


    The result of the following addition:

    123 + 0.0


    A. cannot be evaluated
    B. is equal to 123.0
    C. is equal to 123

    Answer: B


    Explanation:

    Topics: addition operator integer float

    Try it yourself:


    print(123 + 0.0) # 123.0

    If you have an arithmetic operation with a float,

    the result will also be a float.




    Question: 37


    What is the expected output of the following code?


    print(list('hello'))

    A. None of the above.
    B. hello
    C. [h, e, l, l, o]
    D. ['h', 'e', 'l', 'l', 'o']
    E. ['h' 'e' 'l' 'l' 'o']

    Answer: D


    Explanation:

    Topic: list()


    Try it yourself:

    print(list('hello')) # ['h', 'e', 'l', 'l', 'o']

    A string is a sequence of characters


    and works very fine with the list() function.

    The result is a list of strings, in which every character is a string of its own.




    Question: 38


    What is the default return value for a function

    that does not explicitly return any value?


    A. int
    B. void
    C. None
    D. Null
    E. public

    Answer: C

    Explanation:


    Topic: return

    Try it yourself:

    def func1():

    pass

    print(func1()) # None


    def func2():

    return

    print(func2()) # None

    If a function does not have the keyword return the function will return the value None

    The same happens if there is no value after the keyword return





    Question: 39


    Which of the following lines correctly invoke the function defined below:

    def fun(a, b, c=0):




    # Body of the function.

    (Select two answers)


    A. fun(0, 1, 2)
    B. fun(b=0, a=0)
    C. fun(b=1)
    D. fun()


    Answer: A,B


    Explanation:

    Topics: functions positional parameters keyword parameters

    Try it yourself:

    def fun(a, b, c=0):

    # Body of the function.


    pass

    fun(b=0, a=0)

    fun(0, 1, 2)

    # fun() # TypeError: fun() missing 2 required

    # positional arguments: 'a' and 'b'


    # fun(b=1) # TypeError: fun() missing 1 required

    # positional argument: 'a'

    Only the parameter c has a default value.

    Therefore you need at least two arguments.




    Question: 40


    What is the expected output of the following code?


    x = '''

    print(len(x))

    A. 1
    B. 2
    C. The code is erroneous.
    D. 0


    Answer: A


    Explanation:

    Topics: len() escaping

    Try it yourself:

    print(len(''')) # 1


    The backslash is the character to escape another character.

    Here the backslash escapes the following single quote character.

    Together they are one character.




    Question: 41


    Which of the following statements are true? (Select two answers)

    A. The ** operator uses right-sided binding.
    B. The result of the / operator is always an integer value.
    C. The right argument of the % operator cannot be zero.
    D. Addition precedes multiplication.


    Answer: A,B,D


    Explanation:

    Topics: exponentiation/power operator right-sided binding

    Try it yourself:

    print(4 ** 3 ** 2) # 262144

    print(4 ** (3 ** 2)) # 262144


    print(4 ** 9) # 262144

    print(262144) # 262144

    # print(7 % 0) # ZeroDivisionError

    If you have more than one power operators

    next to each other, the right one will be executed first. https://docs.python.org/3/reference/expressions.html#the-power-
    operator To check the rest of a modulo operation,

    Python needs to divide the first operand by the second operand.

    And like in a normal division, the second operand cannot be zero.




    Question: 42

    What do you call a tool that lets you lanch your code step-by-step and inspect it at each moment of execution?


    A. A debugger
    B. An editor
    C. A console

    Answer: A


    Explanation:

    Topic: debugger

    https://en.wikipedia.org/wiki/Debugger





    Question: 43


    What is the expected output of the following code?

    list1 = [1, 3]


    list2 = list1

    list1[0] = 4

    print(list2)


    A. [1, 4]
    B. [4, 3]
    C. [1, 3, 4]
    D. [1, 3]

    Answer: B


    Explanation:

    Topics: list reference of a mutable data type

    Try it yourself:

    list1 = [1, 3]

    list2 = list1


    list1[0] = 4

    print(list2) # [4, 3]

    print(id(list1)) # e.g. 140539383947452


    print(id(list2)) # e.g. 140539383947452 (the same number)

    A list is mutable.

    When you assign it to a different variable, you create a reference of the same object.


    If afterwards you change one of them, the other one is changed too.




    Question: 44


    How many stars will the following code print to the monitor?

    i = 0


    while i <= 3:

    i += 2

    print('*')


    A. one
    B. zero
    C. two
    D. three

    Answer: C


    Explanation:

    Topic: while

    Try it yourself:

    i = 0

    while i <= 3: # i=0, i=2


    i += 2

    print('*')

    """

    *

    *


    """

    In the first iteration of the while loop i is 0

    i becomes 2 and the first star is printed.


    In the second iteration of the while loop i is 2

    i becomes 4 and the second star is printed.

    i is 4 and therefore 4 <= 3 is False what ends the while loop.





    Question: 45


    What is the expected output of the following code if the user enters 2 and 4?

    x = input()

    y = input()


    print(x + y)

    A. 4
    B. 6
    C. 24
    D. 2

    Answer: C


    Explanation:

    Topics: input() plus operator string concatenation


    Try it yourself:

    # x = input()

    # y = input()

    x, y = '2', '4' # Just for convenience

    print(x + y) # 24


    As always the input() function return a string.

    Therefore string concatenation takes place and the result is the string 24








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